domingo, 2 de mayo de 2010

Primeras fotos de Patsy en el Twitter

Patsy Kensit en una escena
de Holby City.
¡Primera foto de Patsy en el Twitter! La imagen de la izquierda (perteneciente al episodio de Holby City emitido el martes, 27 de abril, llamado "What Goes Around") fue posteda por el actor Jaime Zubairi (interpreta a Harvey Posner) en la que él mismo aparece. El actor ha utilizado el Twitter para autopromocionarse en este breve papel.

Estos fueron algunos de los comentarios que hizo al respecto:

andobrien The big reveal... Harvey Posner (el actor Jamie Zubairi) aka @jamiezoob with Patsy Kensit in #holby city http://tweetphoto.com/20157522 . (27/04/2010).

jamiezoob @lberzins_voices I'm debuting in a hospital drama tonight on bbc1. (27/04/2010).
En días posteriores, el actor continuó dando detalles de su paso en la serie:
Patsy en  una escena en Holby City.
jamiezoob @JosephByrneFans @TinaHobleyfans I have a scene with Joseph in June! He's very funny in real life. (29/04/2010).
jamiezoob I posted 16 photos on Facebook in the album "Holby City" http://bit.ly/95cLrl (29/04/2010).

jamiezoob This is for @holbycityfans and @josephbyrneFans from my second ep coming up in June #Holby http://tweetphoto.com/20615578 (01/05/2010).
TinaHobleyfans @jamiezoob Love that photo of you & Luke have you go any scence with patsy Kensit ?x (01/05/2010).
jamiezoob @TinaHobleyfans I did this week and I have in June as well (01/05/2010).
jamiezoob @TinaHobleyfans cast and crew are really friendly and welcoming. It was nice to 'guest' there. (01/05/2010).
jamiezoob @TinaHobleyfans yeah. I haven't worked with Tina yet. I'm hoping they'll bring my character again. (01/05/2010).
 
 pinkandsparkleyx @jamiezoob hey thought u were great in Holby, u should be a regular! Was it cool working with Patsy, is she nice?? (01/05/2010).
jamiezoob@pinkandsparklyx thanks for saying so Susan! Yeah, Patsy was great to work with but bless her she wasn't well during the surgery scene but not that you could tell onscreen! So professional. (01/05/2010).

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